1.
Which of the following is dependent on temperature? (NEET 2017)
(a) Molarity
(b) Mole fraction
(c) Weight percentage
(d) Molality
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2. What is the mole fraction of the solute in a 1.00 m aqueous solution? (2015, 2011)
(a) 1.770 (b) 0.0354
c) 0.0177 (d) 0.177
3. How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO3? The concentrated acid is 70% HNO3. (NEET 2013)
(a) 70.0 g conc. HNO3
(b) 54.0 g conc. HNO3
(c) 45.0 g conc. HNO3
(d) 90.0 g conc. HNO3
4. Which of the following compounds can be used as antifreeze in automobile radiators? (2012)
(a) Methyl alcohol (b) Glycol
(c) Nitro phenol (d) Ethyl alcohol
5. Concentrated aqueous sulphuric acid is 98% H2SO4 by mass and has a density of 1.80 g mL–1. Volume of acid required to make one litre of 0.1 M H2SO4 solution is (2007)
(a) 16.65 mL (b) 22.20 mL
(c) 5.55 mL (d) 11.10 mL
6. The mole fraction of the solute in one molal Aqueous solution is (2005)
(a) 0.009 (b) 0.018
(c) 0.027 (d) 0.036
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7. 2.5 liter of 1 M NaOH solution is mixed with another 3 litre of 0.5 M NaOH solution. Then find out molarity of resultant solution. (2002)
(a) 0.80 M (b) 1.0 M
(c) 0.73 M (d) 0.50 M
12. In water saturated air, the mole fraction of water vapor is 0.02. If the total pressure of the saturated air is 1.2 atm, the partial pressure of dry air is (NEET 2019)
(a) 1.18 atm (b) 1.76 atm
c) 1.176 atm (d) 0.98 atm.
13. PA and pB are the vapour pressures of pure liquid components, A and B, respectively of an ideal binary solution. If xA represents the mole fraction of component A, the total pressure of the solution will be (2012)
(a) pA + xA(pB – pA) (b) pA + xA ( pA – pB)
(c) pB + xA (pB – pA) (d) pB + xA ( pA – pB)
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14. Vapour pressure of chloroform (CHCl3) and dichloromethane (CH2Cl2) at 25°C are 200 mm Hg and 41.5 mm Hg respectively. Vapour pressure of the solution obtained by mixing 25.5 g of CHCl3 and 40 g of CH2Cl2 at the same temperature will be (Molecular mass of CHCl3 = 119.5 u and molecular (Mains 2012) (mass of CH2Cl2 = 85 u)
(a) 173.9 mm Hg (b) 615.0 mm Hg
(c) 347.9 mm Hg (d) 285.5 mm Hg
15. A solution has a 1 : 4 mole ratio of pentane to hexane. The vapour pressures of the pure hydrocarbons at 20 °C are 440 mm Hg for pentane and 120 mm Hg for hexane. The mole fraction of pentane in the vapor phase would be (2005)
(a) 0.200 (b) 0.549
(c) 0.786 (d) 0.478
16. The vapor pressure of two liquids P and Q are 80 and 60 torr, respectively. The total vapors pressure of solution obtained by mixing 3 mole of P and 2 mol of Q would be (2005)
(a) 72 torr (b) 140 torr
(c) 68 torr (d) 20 torr
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17. The mixture which shows positive deviation from Raoul’s law is (NEET 2020)
(a) ethanol + acetone (b) benzene + toluene
(c) acetone + chloroform (d) chloromethane + bromoethane.
18. For an ideal solution, the correct option is (NEET 2019)
(a) ΔmixG = 0 at constant T and P
(b) ΔmixS = 0 at constant T and P
(c) Δmix V ≠ 0 at constant T and P
(d) Δmix H = 0 at constant T and P.
19. The mixture that forms maximum boiling azeotrope is (NEET 2019)
(a) heptane + octane (b) water + nitric acid
(c) ethanol + water (d) acetone + carbon disulphide.
20. Which of the following statements is correct regarding a solution of two components A and B exhibiting positive deviation from ideal behavior? (NEET 2019)
(a) Intermolecular attractive forces between A-A and B-B are stronger than those between A-B.
(b) Δ mix H = 0 at constant T and P.
(c) Δ mix V = 0 at constant T and P.
(d) Intermolecular attractive forces between A-A and B-B are equal to those between A-B.
21. Which one of the following is incorrect for ideal solution? (NEET 2016)
(a) ΔH mix = 0 (b) ΔU mix = 0
(c) ΔP = Pobs – Calculated by Raoult ’s law = 0
(d) ΔG mix = 0
22. Which of the following statements about the composition of the vapors over an ideal 1 : 1 molar mixture of benzene and toluene is correct? Assume that the temperature is constant at 25°C. (Given, vapor pressure data at 25°C, benzene = 12.8 kPa, toluene = 3.85 kPa) (NEET 2016)
(a) The vapors will contain equal amounts of benzene and toluene.
(b) Not enough information is given to make a prediction.
(c) The vapors will contain a higher percentage of benzene.
(d) The vapors will contain a higher percentage of toluene.
23. Which condition is not satisfied by an ideal solution? (NEET 2013)
(a) Δ mix V = 0 (b) Δ m ix S = 0
(c) Obeisance to Raoul’s Law (d) Δ m ix H = 0
24. A solution of acetone in ethanol (2006)
(a) Obeys Raoul’s law
(b) Shows a negative deviation from Raoul’s law
(c) Shows a positive deviation from Raoul’s law
(d) Behaves like a near ideal solution.
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28. The freezing point depression constant (Kf) of benzene is 5.12 K kg mol–1. The freezing point depression for the solution of molality 0.078 m Containing a non-electrolyte solute in benzene is (rounded off up to two decimal places) (NEET 2020)
(a) 0.20 K (b) 0.80 K
(c) 0.40 K (d) 0.60 K
29. If molality of the dilute solution is doubled, the value of molal depression constant (Kf) will be (NEET 2017)
(a) Halved (b) tripled
(c) Unchanged (d) doubled.
30. At 100°C the vapors pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be (NEET 2016)
(a) 102 °C (b) 103 °C
(c) 101 °C (d) 100 °C
31. 200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.57 × 10–3 bar. The molar mass of protein will be (R = 0.083 L bar mol–1 K–1) (Mains 2011)
(a) 51022 g mol–1 (b) 122044 g mol–1
(c) 31011 g mol–1 (d) 61038 g mol–1
32. A solution of sucrose (molar mass = 342 g mol–1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be (Kf for water = 1.86 K kg mol–1) (2010)
(a) – 0.372 °C (b) – 0.520 °C
(c) + 0.372 °C (d) – 0.570 °C
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33. During osmosis, flow of water through a semipermeable membrane is (2006)
(a) From solution having lower concentration only
(b) From solution having higher concentration only
(c) From both sides of semipermeable membrane with equal flow rates
(d) from both sides of semipermeable membrane with unequal flow rates.
34. 1.00 g of a non-electrolyte solute (molar mass 250 g mol–1) was dissolved in 51.2 g of benzene. If the freezing point constant, Kf of benzene is 5.12 K kg mol–1, the freezing point of benzene will be lowered by (2006)
(a) 0.2 K (b) 0.4 K
(c) 0.3 K (d) 0.5 K
35. A solution containing 10 g per dm3 of urea (molecular mass = 60 g mol–1) is isotonic with a 5% solution of a non-volatile solute. The molecular mass of this non-volatile solute is (2006)
(a) 200 g mol–1 (b) 250 g mol–1
(c) 300 g mol–1 (d) 350 g mol–1